Base | Representation |
---|---|
bin | 10010111011111100110… |
… | …101111010000001101011 |
3 | 11121101221101010202111011 |
4 | 102323330311322001223 |
5 | 132310101430110011 |
6 | 2433452533044351 |
7 | 163005655311535 |
oct | 22737465720153 |
9 | 4541841122434 |
10 | 1301322113131 |
11 | 461984453377 |
12 | 1902561866b7 |
13 | 95938ca55c1 |
14 | 46dacdc4855 |
15 | 23cb5032621 |
hex | 12efcd7a06b |
1301322113131 has 4 divisors (see below), whose sum is σ = 1301324560200. Its totient is φ = 1301319666064.
The previous prime is 1301322113123. The next prime is 1301322113219. The reversal of 1301322113131 is 1313112231031.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1301322113131 - 23 = 1301322113123 is a prime.
It is a super-2 number, since 2×13013221131312 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1301322123131) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 51826 + ... + 1614103.
It is an arithmetic number, because the mean of its divisors is an integer number (325331140050).
Almost surely, 21301322113131 is an apocalyptic number.
1301322113131 is a deficient number, since it is larger than the sum of its proper divisors (2447069).
1301322113131 is an equidigital number, since it uses as much as digits as its factorization.
1301322113131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2447068.
The product of its (nonzero) digits is 324, while the sum is 22.
Adding to 1301322113131 its reverse (1313112231031), we get a palindrome (2614434344162).
The spelling of 1301322113131 in words is "one trillion, three hundred one billion, three hundred twenty-two million, one hundred thirteen thousand, one hundred thirty-one".
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