Base | Representation |
---|---|
bin | 1011110101011110110110… |
… | …1010101100010100000111 |
3 | 1201002001222020111112000001 |
4 | 2331113231222230110013 |
5 | 3201203012443100320 |
6 | 43402143205502131 |
7 | 2512122154132246 |
oct | 275275552542407 |
9 | 51061866445001 |
10 | 13013443331335 |
11 | 4167a74556587 |
12 | 1562113a11947 |
13 | 735215b60645 |
14 | 32dbd55d495d |
15 | 1787999ab20a |
hex | bd5edaac507 |
13013443331335 has 16 divisors (see below), whose sum is σ = 15736027484736. Its totient is φ = 10330881434368.
The previous prime is 13013443331323. The next prime is 13013443331359. The reversal of 13013443331335 is 53313334431031.
It is a cyclic number.
It is not a de Polignac number, because 13013443331335 - 25 = 13013443331303 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 13013443331294 and 13013443331303.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1742824 + ... + 5391133.
It is an arithmetic number, because the mean of its divisors is an integer number (983501717796).
Almost surely, 213013443331335 is an apocalyptic number.
13013443331335 is a deficient number, since it is larger than the sum of its proper divisors (2722584153401).
13013443331335 is a wasteful number, since it uses less digits than its factorization.
13013443331335 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 7136762.
The product of its (nonzero) digits is 174960, while the sum is 37.
Adding to 13013443331335 its reverse (53313334431031), we get a palindrome (66326777762366).
The spelling of 13013443331335 in words is "thirteen trillion, thirteen billion, four hundred forty-three million, three hundred thirty-one thousand, three hundred thirty-five".
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