Base | Representation |
---|---|
bin | 1111100000110… |
… | …11010110110101 |
3 | 100001212120022111 |
4 | 13300123112311 |
5 | 231303313402 |
6 | 20525131021 |
7 | 3140063503 |
oct | 760332665 |
9 | 301776274 |
10 | 130135477 |
11 | 6750478a |
12 | 376b9a71 |
13 | 20c65354 |
14 | 133d7673 |
15 | b6589d7 |
hex | 7c1b5b5 |
130135477 has 2 divisors, whose sum is σ = 130135478. Its totient is φ = 130135476.
The previous prime is 130135463. The next prime is 130135483. The reversal of 130135477 is 774531031.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 104673361 + 25462116 = 10231^2 + 5046^2 .
It is a cyclic number.
It is not a de Polignac number, because 130135477 - 27 = 130135349 is a prime.
It is a super-3 number, since 3×1301354773 (a number of 25 digits) contains 333 as substring.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (130135417) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65067738 + 65067739.
It is an arithmetic number, because the mean of its divisors is an integer number (65067739).
Almost surely, 2130135477 is an apocalyptic number.
It is an amenable number.
130135477 is a deficient number, since it is larger than the sum of its proper divisors (1).
130135477 is an equidigital number, since it uses as much as digits as its factorization.
130135477 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8820, while the sum is 31.
The square root of 130135477 is about 11407.6937634212. The cubic root of 130135477 is about 506.7556149143.
The spelling of 130135477 in words is "one hundred thirty million, one hundred thirty-five thousand, four hundred seventy-seven".
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