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1301410232561 is a prime number
BaseRepresentation
bin10010111100000010000…
…110000011100011110001
311121102011111221200121202
4102330002012003203301
5132310242004420221
62433505401500545
7163011105312515
oct22740206034361
94542144850552
101301410232561
11461a1a16a84a
1219027b7a1755
139595131958a
1446dba9a2145
1523cbcb3bd0b
hex12f021838f1

1301410232561 has 2 divisors, whose sum is σ = 1301410232562. Its totient is φ = 1301410232560.

The previous prime is 1301410232497. The next prime is 1301410232611. The reversal of 1301410232561 is 1652320141031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1121947008400 + 179463224161 = 1059220^2 + 423631^2 .

It is a cyclic number.

It is not a de Polignac number, because 1301410232561 - 26 = 1301410232497 is a prime.

It is a super-2 number, since 2×13014102325612 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1301410232261) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 650705116280 + 650705116281.

It is an arithmetic number, because the mean of its divisors is an integer number (650705116281).

Almost surely, 21301410232561 is an apocalyptic number.

It is an amenable number.

1301410232561 is a deficient number, since it is larger than the sum of its proper divisors (1).

1301410232561 is an equidigital number, since it uses as much as digits as its factorization.

1301410232561 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4320, while the sum is 29.

Adding to 1301410232561 its reverse (1652320141031), we get a palindrome (2953730373592).

The spelling of 1301410232561 in words is "one trillion, three hundred one billion, four hundred ten million, two hundred thirty-two thousand, five hundred sixty-one".