130141111032203 has 4 divisors (see below), whose sum is σ = 130141240409208. Its totient is φ = 130140981655200.

The previous prime is 130141111032193. The next prime is 130141111032217. The reversal of 130141111032203 is 302230111141031.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 130141111032203 - 2¹⁶ = 130141110966667 is a prime.

It is a super-4 number, since 4×130141111032203⁴ (a number of 58 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (130141111032403) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 63167726 + ... + 65195427.

It is an arithmetic number, because the mean of its divisors is an integer number (32535310102302).

Almost surely, 2^{130141111032203} is an apocalyptic number.

130141111032203 is a deficient number, since it is larger than the sum of its proper divisors (129377005).

130141111032203 is a wasteful number, since it uses less digits than its factorization.

130141111032203 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 129377004.

The product of its (nonzero) digits is 432, while the sum is 23.

Adding to 130141111032203 its reverse (302230111141031), we get a palindrome (432371222173234).

The spelling of 130141111032203 in words is "one hundred thirty trillion, one hundred forty-one billion, one hundred eleven million, thirty-two thousand, two hundred three".