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130141299205447 is a prime number
BaseRepresentation
bin11101100101110011100001…
…111010001110010101000111
3122001210101102220101122100021
4131211303201322032111013
5114024213340044033242
61140442030522200011
736261253500141655
oct3545634172162507
9561711386348307
10130141299205447
1138515684696682
121271a309953007
13578036c3645aa
14241cc30181dd5
15100a41939eb67
hex765ce1e8e547

130141299205447 has 2 divisors, whose sum is σ = 130141299205448. Its totient is φ = 130141299205446.

The previous prime is 130141299205391. The next prime is 130141299205471. The reversal of 130141299205447 is 744502992141031.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 130141299205447 - 223 = 130141290816839 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 130141299205394 and 130141299205403.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (130141299205847) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65070649602723 + 65070649602724.

It is an arithmetic number, because the mean of its divisors is an integer number (65070649602724).

Almost surely, 2130141299205447 is an apocalyptic number.

130141299205447 is a deficient number, since it is larger than the sum of its proper divisors (1).

130141299205447 is an equidigital number, since it uses as much as digits as its factorization.

130141299205447 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2177280, while the sum is 52.

The spelling of 130141299205447 in words is "one hundred thirty trillion, one hundred forty-one billion, two hundred ninety-nine million, two hundred five thousand, four hundred forty-seven".