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13014320001 = 34338106667
BaseRepresentation
bin11000001111011011…
…01100001110000001
31020120222201221210220
430013231230032001
5203123131220001
65551222013253
7640335615624
oct140755541601
936528657726
1013014320001
115579276271
122632577229
1312c5346987
148b6615dbb
1551282ec36
hex307b6c381

13014320001 has 4 divisors (see below), whose sum is σ = 17352426672. Its totient is φ = 8676213332.

The previous prime is 13014319993. The next prime is 13014320089. The reversal of 13014320001 is 10002341031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13014320001 - 23 = 13014319993 is a prime.

It is not an unprimeable number, because it can be changed into a prime (13014320701) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2169053331 + ... + 2169053336.

It is an arithmetic number, because the mean of its divisors is an integer number (4338106668).

Almost surely, 213014320001 is an apocalyptic number.

It is an amenable number.

13014320001 is a deficient number, since it is larger than the sum of its proper divisors (4338106671).

13014320001 is an equidigital number, since it uses as much as digits as its factorization.

13014320001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4338106670.

The product of its (nonzero) digits is 72, while the sum is 15.

Adding to 13014320001 its reverse (10002341031), we get a palindrome (23016661032).

The spelling of 13014320001 in words is "thirteen billion, fourteen million, three hundred twenty thousand, one".

Divisors: 1 3 4338106667 13014320001