130144214024232 has 16 divisors (see below), whose sum is σ = 325360535060640. Its totient is φ = 43381404674736.

The previous prime is 130144214024219. The next prime is 130144214024239. The reversal of 130144214024232 is 232420412441031.

It is a junction number, because it is equal to n+sod(n) for n = 130144214024193 and 130144214024202.

It is not an unprimeable number, because it can be changed into a prime (130144214024239) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2711337792148 + ... + 2711337792195.

It is an arithmetic number, because the mean of its divisors is an integer number (20335033441290).

Almost surely, 2^{130144214024232} is an apocalyptic number.

130144214024232 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

130144214024232 is an abundant number, since it is smaller than the sum of its proper divisors (195216321036408).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

130144214024232 is a wasteful number, since it uses less digits than its factorization.

130144214024232 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5422675584352 (or 5422675584348 counting only the distinct ones).

The product of its (nonzero) digits is 36864, while the sum is 33.

Adding to 130144214024232 its reverse (232420412441031), we get a palindrome (362564626465263).

The spelling of 130144214024232 in words is "one hundred thirty trillion, one hundred forty-four billion, two hundred fourteen million, twenty-four thousand, two hundred thirty-two".