13014433 has 4 divisors (see below), whose sum is σ = 13021888. Its totient is φ = 13006980.

The previous prime is 13014427. The next prime is 13014461. The reversal of 13014433 is 33441031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 13014433 - 2⁹ = 13013921 is a prime.

It is a super-2 number, since 2×13014433² = 338750932622978, which contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 13014433.

It is not an unprimeable number, because it can be changed into a prime (13014403) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 460 + ... + 5122.

It is an arithmetic number, because the mean of its divisors is an integer number (3255472).

Almost surely, 2^13014433 is an apocalyptic number.

It is an amenable number.

13014433 is a deficient number, since it is larger than the sum of its proper divisors (7455).

13014433 is an equidigital number, since it uses as much as digits as its factorization.

13014433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7454.

The product of its (nonzero) digits is 432, while the sum is 19.

The square root of 13014433 is about 3607.5522172243. The cubic root of 13014433 is about 235.2204540594.

Adding to 13014433 its reverse (33441031), we get a palindrome (46455464).

The spelling of 13014433 in words is "thirteen million, fourteen thousand, four hundred thirty-three".