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13014440223 = 34338146741
BaseRepresentation
bin11000001111011100…
…01001100100011111
31020120222222001201120
430013232021210133
5203123144041343
65551224342023
7640336626261
oct140756114437
936528861646
1013014440223
115579348624
122632614913
1312c5389605
148b6647b31
15512855683
hex307b8991f

13014440223 has 4 divisors (see below), whose sum is σ = 17352586968. Its totient is φ = 8676293480.

The previous prime is 13014440209. The next prime is 13014440233. The reversal of 13014440223 is 32204441031.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13014440223 - 24 = 13014440207 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13014440193 and 13014440202.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13014440233) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2169073368 + ... + 2169073373.

It is an arithmetic number, because the mean of its divisors is an integer number (4338146742).

Almost surely, 213014440223 is an apocalyptic number.

13014440223 is a deficient number, since it is larger than the sum of its proper divisors (4338146745).

13014440223 is an equidigital number, since it uses as much as digits as its factorization.

13014440223 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4338146744.

The product of its (nonzero) digits is 2304, while the sum is 24.

Adding to 13014440223 its reverse (32204441031), we get a palindrome (45218881254).

The spelling of 13014440223 in words is "thirteen billion, fourteen million, four hundred forty thousand, two hundred twenty-three".

Divisors: 1 3 4338146741 13014440223