Base | Representation |
---|---|
bin | 11101100101110110011101… |
… | …010111001000110010010111 |
3 | 122001210200120002010001222201 |
4 | 131211312131113020302113 |
5 | 114024241310143434221 |
6 | 1140443310544505331 |
7 | 36261424435412431 |
oct | 3545663527106227 |
9 | 561720502101881 |
10 | 130144444124311 |
11 | 38516a48938781 |
12 | 1271aa4701b247 |
13 | 5780750a89026 |
14 | 241d04bb0d651 |
15 | 100a55051c891 |
hex | 765d9d5c8c97 |
130144444124311 has 2 divisors, whose sum is σ = 130144444124312. Its totient is φ = 130144444124310.
The previous prime is 130144444124293. The next prime is 130144444124323. The reversal of 130144444124311 is 113421444441031.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 130144444124311 - 223 = 130144435735703 is a prime.
It is a super-4 number, since 4×1301444441243114 (a number of 58 digits) contains 4444 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (130144444124011) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65072222062155 + 65072222062156.
It is an arithmetic number, because the mean of its divisors is an integer number (65072222062156).
Almost surely, 2130144444124311 is an apocalyptic number.
130144444124311 is a deficient number, since it is larger than the sum of its proper divisors (1).
130144444124311 is an equidigital number, since it uses as much as digits as its factorization.
130144444124311 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 73728, while the sum is 37.
Adding to 130144444124311 its reverse (113421444441031), we get a palindrome (243565888565342).
The spelling of 130144444124311 in words is "one hundred thirty trillion, one hundred forty-four billion, four hundred forty-four million, one hundred twenty-four thousand, three hundred eleven".
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