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13014450035369 is a prime number
BaseRepresentation
bin1011110101100010100110…
…1010111101101010101001
31201002011120101210101022122
42331120221222331222221
53201212043202112434
643402431131001025
72512156130024366
oct275305152755251
951064511711278
1013014450035369
114168440839192
121562354b99175
137353465a70c3
1432dc8d1a946d
15178808063c2e
hexbd629abdaa9

13014450035369 has 2 divisors, whose sum is σ = 13014450035370. Its totient is φ = 13014450035368.

The previous prime is 13014450035341. The next prime is 13014450035371. The reversal of 13014450035369 is 96353005441031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8325319641769 + 4689130393600 = 2885363^2 + 2165440^2 .

It is a cyclic number.

It is not a de Polignac number, because 13014450035369 - 28 = 13014450035113 is a prime.

It is a super-2 number, since 2×130144500353692 (a number of 27 digits) contains 22 as substring.

Together with 13014450035371, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (13014450085369) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6507225017684 + 6507225017685.

It is an arithmetic number, because the mean of its divisors is an integer number (6507225017685).

Almost surely, 213014450035369 is an apocalyptic number.

It is an amenable number.

13014450035369 is a deficient number, since it is larger than the sum of its proper divisors (1).

13014450035369 is an equidigital number, since it uses as much as digits as its factorization.

13014450035369 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 583200, while the sum is 44.

The spelling of 13014450035369 in words is "thirteen trillion, fourteen billion, four hundred fifty million, thirty-five thousand, three hundred sixty-nine".