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1301450107 is a prime number
BaseRepresentation
bin100110110010010…
…1000110101111011
310100200220111220211
41031210220311323
510131132400412
6333050331551
744152100116
oct11544506573
93320814824
101301450107
116086a8801
12303a29bb7
13179825029
14c4bbb57d
15793c9ca7
hex4d928d7b

1301450107 has 2 divisors, whose sum is σ = 1301450108. Its totient is φ = 1301450106.

The previous prime is 1301450089. The next prime is 1301450119. The reversal of 1301450107 is 7010541031.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1301450107 - 211 = 1301448059 is a prime.

It is a super-2 number, since 2×13014501072 = 3387544762020622898, which contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1301450177) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 650725053 + 650725054.

It is an arithmetic number, because the mean of its divisors is an integer number (650725054).

Almost surely, 21301450107 is an apocalyptic number.

1301450107 is a deficient number, since it is larger than the sum of its proper divisors (1).

1301450107 is an equidigital number, since it uses as much as digits as its factorization.

1301450107 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 420, while the sum is 22.

The square root of 1301450107 is about 36075.6165158684. The cubic root of 1301450107 is about 1091.7985364879.

Adding to 1301450107 its reverse (7010541031), we get a palindrome (8311991138).

The spelling of 1301450107 in words is "one billion, three hundred one million, four hundred fifty thousand, one hundred seven".