Base | Representation |
---|---|
bin | 11101100101111111011000… |
… | …110010101111110011010101 |
3 | 122001211121022012210120001221 |
4 | 131211333120302233303111 |
5 | 114024420423433333331 |
6 | 1140451534140050341 |
7 | 36262214136664450 |
oct | 3545773062576325 |
9 | 561747265716057 |
10 | 130154031152341 |
11 | 38520018527839 |
12 | 127208818339b1 |
13 | 578161b042691 |
14 | 241d6bb092497 |
15 | 100a912003711 |
hex | 765fd8cafcd5 |
130154031152341 has 32 divisors (see below), whose sum is σ = 155471909257728. Its totient is φ = 106533483724800.
The previous prime is 130154031152317. The next prime is 130154031152371. The reversal of 130154031152341 is 143251130451031.
It is a cyclic number.
It is not a de Polignac number, because 130154031152341 - 237 = 130016592198869 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 130154031152297 and 130154031152306.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (130154031152371) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 235043791 + ... + 235596883.
It is an arithmetic number, because the mean of its divisors is an integer number (4858497164304).
Almost surely, 2130154031152341 is an apocalyptic number.
It is an amenable number.
130154031152341 is a deficient number, since it is larger than the sum of its proper divisors (25317878105387).
130154031152341 is a wasteful number, since it uses less digits than its factorization.
130154031152341 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 555541.
The product of its (nonzero) digits is 21600, while the sum is 34.
The spelling of 130154031152341 in words is "one hundred thirty trillion, one hundred fifty-four billion, thirty-one million, one hundred fifty-two thousand, three hundred forty-one".
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