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130166506471 is a prime number
BaseRepresentation
bin111100100111010000…
…1110100001111100111
3110102222112020122120011
41321032201310033213
54113040111201341
6135444143551051
712255435022651
oct1711641641747
9412875218504
10130166506471
1150226665991
12212885bb487
13c375532981
14642b64d6d1
1535bc7a3b81
hex1e4e8743e7

130166506471 has 2 divisors, whose sum is σ = 130166506472. Its totient is φ = 130166506470.

The previous prime is 130166506447. The next prime is 130166506487. The reversal of 130166506471 is 174605661031.

130166506471 = T294579 + T294580 + T294581.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 130166506471 - 211 = 130166504423 is a prime.

It is a super-3 number, since 3×1301665064713 (a number of 34 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (130166506411) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65083253235 + 65083253236.

It is an arithmetic number, because the mean of its divisors is an integer number (65083253236).

Almost surely, 2130166506471 is an apocalyptic number.

130166506471 is the 294581-st centered triangular number.

130166506471 is a deficient number, since it is larger than the sum of its proper divisors (1).

130166506471 is an equidigital number, since it uses as much as digits as its factorization.

130166506471 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 90720, while the sum is 40.

The spelling of 130166506471 in words is "one hundred thirty billion, one hundred sixty-six million, five hundred six thousand, four hundred seventy-one".