Base | Representation |
---|---|
bin | 111100101000001111… |
… | …1001010111101001100 |
3 | 110110001211002011102022 |
4 | 1321100133022331030 |
5 | 4113122014230000 |
6 | 135451320145312 |
7 | 12256314235466 |
oct | 1712037127514 |
9 | 413054064368 |
10 | 130199367500 |
11 | 5024316a964 |
12 | 21297608238 |
13 | c37c299c77 |
14 | 6431b65136 |
15 | 35c05e5585 |
hex | 1e507caf4c |
130199367500 has 60 divisors (see below), whose sum is σ = 286366708320. Its totient is φ = 51778536000.
The previous prime is 130199367499. The next prime is 130199367503. The reversal of 130199367500 is 5763991031.
It is not an unprimeable number, because it can be changed into a prime (130199367503) by changing a digit.
It is a polite number, since it can be written in 19 ways as a sum of consecutive naturals, for example, 281981 + ... + 583019.
It is an arithmetic number, because the mean of its divisors is an integer number (4772778472).
Almost surely, 2130199367500 is an apocalyptic number.
130199367500 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 130199367500, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (143183354160).
130199367500 is an abundant number, since it is smaller than the sum of its proper divisors (156167340820).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
130199367500 is a wasteful number, since it uses less digits than its factorization.
130199367500 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 301236 (or 301219 counting only the distinct ones).
The product of its (nonzero) digits is 153090, while the sum is 44.
The spelling of 130199367500 in words is "one hundred thirty billion, one hundred ninety-nine million, three hundred sixty-seven thousand, five hundred".
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