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13020034433 = 71860004919
BaseRepresentation
bin11000010000000110…
…11111010110000001
31020121101111021112112
430020003133112001
5203131112100213
65551544305105
7640435316030
oct141003372601
936541437475
1013020034433
11558151963a
122634472195
1312c65979b3
148b72a2717
155130acea8
hex3080df581

13020034433 has 4 divisors (see below), whose sum is σ = 14880039360. Its totient is φ = 11160029508.

The previous prime is 13020034421. The next prime is 13020034463. The reversal of 13020034433 is 33443002031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13020034433 - 28 = 13020034177 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13020034399 and 13020034408.

It is not an unprimeable number, because it can be changed into a prime (13020034463) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 930002453 + ... + 930002466.

It is an arithmetic number, because the mean of its divisors is an integer number (3720009840).

Almost surely, 213020034433 is an apocalyptic number.

It is an amenable number.

13020034433 is a deficient number, since it is larger than the sum of its proper divisors (1860004927).

13020034433 is an equidigital number, since it uses as much as digits as its factorization.

13020034433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1860004926.

The product of its (nonzero) digits is 2592, while the sum is 23.

Adding to 13020034433 its reverse (33443002031), we get a palindrome (46463036464).

The spelling of 13020034433 in words is "thirteen billion, twenty million, thirty-four thousand, four hundred thirty-three".

Divisors: 1 7 1860004919 13020034433