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130200594262421 is a prime number
BaseRepresentation
bin11101100110101010110000…
…001010111010100110010101
3122002000001111021111122001112
4131212222300022322212111
5114031201304112344141
61140525154405104405
736265453046620124
oct3546526012724625
9562001437448045
10130200594262421
11385388421585a1
12127298b76b8105
135785b2ba41517
142421a57171abb
15100bc39ca57eb
hex766ab02ba995

130200594262421 has 2 divisors, whose sum is σ = 130200594262422. Its totient is φ = 130200594262420.

The previous prime is 130200594262393. The next prime is 130200594262429. The reversal of 130200594262421 is 124262495002031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 123841598155396 + 6358996107025 = 11128414^2 + 2521705^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-130200594262421 is a prime.

It is a super-3 number, since 3×1302005942624213 (a number of 43 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (130200594262429) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65100297131210 + 65100297131211.

It is an arithmetic number, because the mean of its divisors is an integer number (65100297131211).

Almost surely, 2130200594262421 is an apocalyptic number.

It is an amenable number.

130200594262421 is a deficient number, since it is larger than the sum of its proper divisors (1).

130200594262421 is an equidigital number, since it uses as much as digits as its factorization.

130200594262421 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 207360, while the sum is 41.

The spelling of 130200594262421 in words is "one hundred thirty trillion, two hundred billion, five hundred ninety-four million, two hundred sixty-two thousand, four hundred twenty-one".