130202444142433 has 4 divisors (see below), whose sum is σ = 140218016768788. Its totient is φ = 120186871516080.

The previous prime is 130202444142431. The next prime is 130202444142439. The reversal of 130202444142433 is 334241444202031.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 5282748286929 + 124919695855504 = 2298423^2 + 11176748^2 .

It is a cyclic number.

It is not a de Polignac number, because 130202444142433 - 2¹ = 130202444142431 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 130202444142392 and 130202444142401.

It is not an unprimeable number, because it can be changed into a prime (130202444142431) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5007786313158 + ... + 5007786313183.

It is an arithmetic number, because the mean of its divisors is an integer number (35054504192197).

Almost surely, 2^{130202444142433} is an apocalyptic number.

130202444142433 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

130202444142433 is a deficient number, since it is larger than the sum of its proper divisors (10015572626355).

130202444142433 is a wasteful number, since it uses less digits than its factorization.

130202444142433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 10015572626354.

The product of its (nonzero) digits is 221184, while the sum is 37.

Adding to 130202444142433 its reverse (334241444202031), we get a palindrome (464443888344464).

The spelling of 130202444142433 in words is "one hundred thirty trillion, two hundred two billion, four hundred forty-four million, one hundred forty-two thousand, four hundred thirty-three".