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130203033299981 is a prime number
BaseRepresentation
bin11101100110101101000001…
…100011000110110000001101
3122002000021210020222120120222
4131212231001203012300031
5114031221303011044411
61140530240414121125
736265600354242605
oct3546550143066015
9562007706876528
10130203033299981
1138539883a03614
121272a2784b01a5
13578612a147905
142421c09073c05
15100bd2de8d4db
hex766b418c6c0d

130203033299981 has 2 divisors, whose sum is σ = 130203033299982. Its totient is φ = 130203033299980.

The previous prime is 130203033299881. The next prime is 130203033300001. The reversal of 130203033299981 is 189992330302031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 130139977067881 + 63056232100 = 11407891^2 + 251110^2 .

It is a cyclic number.

It is not a de Polignac number, because 130203033299981 - 210 = 130203033298957 is a prime.

It is a super-2 number, since 2×1302030332999812 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (130203033299881) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65101516649990 + 65101516649991.

It is an arithmetic number, because the mean of its divisors is an integer number (65101516649991).

Almost surely, 2130203033299981 is an apocalyptic number.

It is an amenable number.

130203033299981 is a deficient number, since it is larger than the sum of its proper divisors (1).

130203033299981 is an equidigital number, since it uses as much as digits as its factorization.

130203033299981 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1889568, while the sum is 53.

The spelling of 130203033299981 in words is "one hundred thirty trillion, two hundred three billion, thirty-three million, two hundred ninety-nine thousand, nine hundred eighty-one".