Base | Representation |
---|---|
bin | 11101100110101101011001… |
… | …011011101111000101111011 |
3 | 122002000022211012000022211012 |
4 | 131212231121123233011323 |
5 | 114031223113102134433 |
6 | 1140530344251024135 |
7 | 36265613321310302 |
oct | 3546553133570573 |
9 | 562008735008735 |
10 | 130203434021243 |
11 | 38539a6a121410 |
12 | 1272a36a73b04b |
13 | 578619217c59b |
14 | 2421c46385439 |
15 | 100bd54245848 |
hex | 766b596ef17b |
130203434021243 has 4 divisors (see below), whose sum is σ = 142040109841368. Its totient is φ = 118366758201120.
The previous prime is 130203434021189. The next prime is 130203434021263. The reversal of 130203434021243 is 342120434302031.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 130203434021243 - 238 = 129928556114299 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (130203434021263) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5918337910046 + ... + 5918337910067.
It is an arithmetic number, because the mean of its divisors is an integer number (35510027460342).
Almost surely, 2130203434021243 is an apocalyptic number.
130203434021243 is a deficient number, since it is larger than the sum of its proper divisors (11836675820125).
130203434021243 is a wasteful number, since it uses less digits than its factorization.
130203434021243 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 11836675820124.
The product of its (nonzero) digits is 41472, while the sum is 32.
Adding to 130203434021243 its reverse (342120434302031), we get a palindrome (472323868323274).
The spelling of 130203434021243 in words is "one hundred thirty trillion, two hundred three billion, four hundred thirty-four million, twenty-one thousand, two hundred forty-three".
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