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130205244342451 is a prime number
BaseRepresentation
bin11101100110101111000101…
…010101100100000010110011
3122002000111111100110011122211
4131212233011111210002303
5114031240320022424301
61140531244040312551
736266006222632555
oct3546570525440263
9562014440404584
10130205244342451
113853a808a95543
121272a794a72757
1357863c0244475
142421d789874d5
15100be0d13c051
hex766bc55640b3

130205244342451 has 2 divisors, whose sum is σ = 130205244342452. Its totient is φ = 130205244342450.

The previous prime is 130205244342347. The next prime is 130205244342491. The reversal of 130205244342451 is 154243442502031.

It is an a-pointer prime, because the next prime (130205244342491) can be obtained adding 130205244342451 to its sum of digits (40).

It is a strong prime.

It is an emirp because it is prime and its reverse (154243442502031) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 130205244342451 - 223 = 130205235953843 is a prime.

It is not a weakly prime, because it can be changed into another prime (130205244342491) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65102622171225 + 65102622171226.

It is an arithmetic number, because the mean of its divisors is an integer number (65102622171226).

Almost surely, 2130205244342451 is an apocalyptic number.

130205244342451 is a deficient number, since it is larger than the sum of its proper divisors (1).

130205244342451 is an equidigital number, since it uses as much as digits as its factorization.

130205244342451 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 460800, while the sum is 40.

Adding to 130205244342451 its reverse (154243442502031), we get a palindrome (284448686844482).

The spelling of 130205244342451 in words is "one hundred thirty trillion, two hundred five billion, two hundred forty-four million, three hundred forty-two thousand, four hundred fifty-one".