Base | Representation |
---|---|
bin | 111100101000100011… |
… | …1101110110010000111 |
3 | 110110002120002100110212 |
4 | 1321101013232302013 |
5 | 4113132230000012 |
6 | 135452340110035 |
7 | 12256503511163 |
oct | 1712107566207 |
9 | 413076070425 |
10 | 130210000007 |
11 | 5024917225a |
12 | 2129b09531b |
13 | c3815506a9 |
14 | 6433331ca3 |
15 | 35c14e5b22 |
hex | 1e511eec87 |
130210000007 has 2 divisors, whose sum is σ = 130210000008. Its totient is φ = 130210000006.
The previous prime is 130210000001. The next prime is 130210000061. The reversal of 130210000007 is 700000012031.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 130210000007 - 210 = 130209998983 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 130209999946 and 130210000000.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (130210000001) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65105000003 + 65105000004.
It is an arithmetic number, because the mean of its divisors is an integer number (65105000004).
Almost surely, 2130210000007 is an apocalyptic number.
130210000007 is a deficient number, since it is larger than the sum of its proper divisors (1).
130210000007 is an equidigital number, since it uses as much as digits as its factorization.
130210000007 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 42, while the sum is 14.
Adding to 130210000007 its reverse (700000012031), we get a palindrome (830210012038).
The spelling of 130210000007 in words is "one hundred thirty billion, two hundred ten million, seven", and thus it is an aban number.
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