Base | Representation |
---|---|
bin | 11000010000001110… |
… | …01100000011100001 |
3 | 1020121110022112112110 |
4 | 30020013030003201 |
5 | 203131334112001 |
6 | 5552021145533 |
7 | 640446464535 |
oct | 141007140341 |
9 | 36543275473 |
10 | 13021004001 |
11 | 5582021035 |
12 | 263485b2a9 |
13 | 12c68470c5 |
14 | 8b7475bc5 |
15 | 5132003d6 |
hex | 3081cc0e1 |
13021004001 has 4 divisors (see below), whose sum is σ = 17361338672. Its totient is φ = 8680669332.
The previous prime is 13021003993. The next prime is 13021004011. The reversal of 13021004001 is 10040012031.
It is a happy number.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is not a de Polignac number, because 13021004001 - 23 = 13021003993 is a prime.
It is a super-3 number, since 3×130210040013 (a number of 31 digits) contains 333 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13021004011) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2170167331 + ... + 2170167336.
It is an arithmetic number, because the mean of its divisors is an integer number (4340334668).
Almost surely, 213021004001 is an apocalyptic number.
It is an amenable number.
13021004001 is a deficient number, since it is larger than the sum of its proper divisors (4340334671).
13021004001 is an equidigital number, since it uses as much as digits as its factorization.
13021004001 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4340334670.
The product of its (nonzero) digits is 24, while the sum is 12.
Adding to 13021004001 its reverse (10040012031), we get a palindrome (23061016032).
The spelling of 13021004001 in words is "thirteen billion, twenty-one million, four thousand, one".
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