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130210323320023 is a prime number
BaseRepresentation
bin11101100110110011110100…
…000100010100110011010111
3122002000222121022102222002021
4131212303310010110303113
5114031331220232220043
61140533444032354011
736266246124344422
oct3546636404246327
9562028538388067
10130210323320023
1138541984a35571
121272b7719a5907
135786a1c565c3b
1424222db3269b9
15100c108e943ed
hex766cf4114cd7

130210323320023 has 2 divisors, whose sum is σ = 130210323320024. Its totient is φ = 130210323320022.

The previous prime is 130210323320017. The next prime is 130210323320087. The reversal of 130210323320023 is 320023323012031.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 130210323320023 - 29 = 130210323319511 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 130210323320023.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (130210323320123) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65105161660011 + 65105161660012.

It is an arithmetic number, because the mean of its divisors is an integer number (65105161660012).

Almost surely, 2130210323320023 is an apocalyptic number.

130210323320023 is a deficient number, since it is larger than the sum of its proper divisors (1).

130210323320023 is an equidigital number, since it uses as much as digits as its factorization.

130210323320023 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3888, while the sum is 25.

Adding to 130210323320023 its reverse (320023323012031), we get a palindrome (450233646332054).

The spelling of 130210323320023 in words is "one hundred thirty trillion, two hundred ten billion, three hundred twenty-three million, three hundred twenty thousand, twenty-three".