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130212314431 = 282194614349
BaseRepresentation
bin111100101000101000…
…0100011110100111111
3110110002201102221021021
41321101100203310333
54113133323030211
6135452501445011
712256532260603
oct1712120436477
9413081387237
10130212314431
115024a503101
122129ba10767
13c381b80c84
146433775503
1535c1801771
hex1e51423d3f

130212314431 has 4 divisors (see below), whose sum is σ = 130216957000. Its totient is φ = 130207671864.

The previous prime is 130212314429. The next prime is 130212314447. The reversal of 130212314431 is 134413212031.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 130212314431 - 21 = 130212314429 is a prime.

It is a super-2 number, since 2×1302123144312 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 130212314396 and 130212314405.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (130212314831) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2278956 + ... + 2335393.

It is an arithmetic number, because the mean of its divisors is an integer number (32554239250).

Almost surely, 2130212314431 is an apocalyptic number.

130212314431 is a deficient number, since it is larger than the sum of its proper divisors (4642569).

130212314431 is an equidigital number, since it uses as much as digits as its factorization.

130212314431 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4642568.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 130212314431 its reverse (134413212031), we get a palindrome (264625526462).

The spelling of 130212314431 in words is "one hundred thirty billion, two hundred twelve million, three hundred fourteen thousand, four hundred thirty-one".

Divisors: 1 28219 4614349 130212314431