13021311311233 has 4 divisors (see below), whose sum is σ = 13053783409668. Its totient is φ = 12988839212800.

The previous prime is 13021311311221. The next prime is 13021311311279. The reversal of 13021311311233 is 33211311312031.

13021311311233 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 6270501785409 + 6750809525824 = 2504097^2 + 2598232^2 .

It is a cyclic number.

It is not a de Polignac number, because 13021311311233 - 2¹³ = 13021311303041 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13021311311198 and 13021311311207.

It is not an unprimeable number, because it can be changed into a prime (13021311381233) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 16236048616 + ... + 16236049417.

It is an arithmetic number, because the mean of its divisors is an integer number (3263445852417).

Almost surely, 2^{13021311311233} is an apocalyptic number.

It is an amenable number.

13021311311233 is a deficient number, since it is larger than the sum of its proper divisors (32472098435).

13021311311233 is an equidigital number, since it uses as much as digits as its factorization.

13021311311233 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 32472098434.

The product of its (nonzero) digits is 972, while the sum is 25.

Adding to 13021311311233 its reverse (33211311312031), we get a palindrome (46232622623264).

The spelling of 13021311311233 in words is "thirteen trillion, twenty-one billion, three hundred eleven million, three hundred eleven thousand, two hundred thirty-three".