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130213121202000 = 24325337787248431
BaseRepresentation
bin11101100110110110011010…
…110101011001011101010000
3122002001020211022011002121200
4131212312122311121131100
5114031402433011431000
61140535025420551200
736266405350061634
oct3546663265313520
9562036738132550
10130213121202000
11385430902a6721
12127302129b2500
1357870771010c5
1424224c4b58dc4
15100c21e911500
hex766d9ad59750

130213121202000 has 480 divisors, whose sum is σ = 467678057593344. Its totient is φ = 33741961344000.

The previous prime is 130213121201993. The next prime is 130213121202001. The reversal of 130213121202000 is 202121312031.

130213121202000 is a `hidden beast` number, since 1 + 30 + 2 + 1 + 312 + 120 + 200 + 0 = 666.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (130213121202001) by changing a digit.

It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 524017785 + ... + 524266215.

Almost surely, 2130213121202000 is an apocalyptic number.

130213121202000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 130213121202000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (233839028796672).

130213121202000 is an abundant number, since it is smaller than the sum of its proper divisors (337464936391344).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

130213121202000 is a wasteful number, since it uses less digits than its factorization.

130213121202000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 249284 (or 249265 counting only the distinct ones).

The product of its (nonzero) digits is 144, while the sum is 18.

Adding to 130213121202000 its reverse (202121312031), we get a palindrome (130415242514031).

The spelling of 130213121202000 in words is "one hundred thirty trillion, two hundred thirteen billion, one hundred twenty-one million, two hundred two thousand".