Base | Representation |
---|---|
bin | 11101100110110110100101… |
… | …011111111011100110010011 |
3 | 122002001021021202211021112022 |
4 | 131212312211133323212103 |
5 | 114031403314312432201 |
6 | 1140535055251522055 |
7 | 36266412651640364 |
oct | 3546664537734623 |
9 | 562037252737468 |
10 | 130213300124051 |
11 | 385431722a2491 |
12 | 127302628b932b |
13 | 57870a51b8441 |
14 | 2422500811b6b |
15 | 100c2304a541b |
hex | 766da57fb993 |
130213300124051 has 2 divisors, whose sum is σ = 130213300124052. Its totient is φ = 130213300124050.
The previous prime is 130213300124023. The next prime is 130213300124123. The reversal of 130213300124051 is 150421003312031.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-130213300124051 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 130213300124051.
It is not a weakly prime, because it can be changed into another prime (130213300124851) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65106650062025 + 65106650062026.
It is an arithmetic number, because the mean of its divisors is an integer number (65106650062026).
Almost surely, 2130213300124051 is an apocalyptic number.
130213300124051 is a deficient number, since it is larger than the sum of its proper divisors (1).
130213300124051 is an equidigital number, since it uses as much as digits as its factorization.
130213300124051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2160, while the sum is 26.
Adding to 130213300124051 its reverse (150421003312031), we get a palindrome (280634303436082).
The spelling of 130213300124051 in words is "one hundred thirty trillion, two hundred thirteen billion, three hundred million, one hundred twenty-four thousand, fifty-one".
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