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130214145253 is a prime number
BaseRepresentation
bin111100101000101011…
…1100010110011100101
3110110002211212221200111
41321101113202303211
54113134310122003
6135453005013021
712256553654353
oct1712127426345
9413084787614
10130214145253
1150250543685
12212a0554171
13c3823723ba
146433ad07d3
1535c1a63e6d
hex1e515e2ce5

130214145253 has 2 divisors, whose sum is σ = 130214145254. Its totient is φ = 130214145252.

The previous prime is 130214145241. The next prime is 130214145287. The reversal of 130214145253 is 352541412031.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 128348078049 + 1866067204 = 358257^2 + 43198^2 .

It is a cyclic number.

It is not a de Polignac number, because 130214145253 - 221 = 130212048101 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (130214145223) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65107072626 + 65107072627.

It is an arithmetic number, because the mean of its divisors is an integer number (65107072627).

Almost surely, 2130214145253 is an apocalyptic number.

It is an amenable number.

130214145253 is a deficient number, since it is larger than the sum of its proper divisors (1).

130214145253 is an equidigital number, since it uses as much as digits as its factorization.

130214145253 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 14400, while the sum is 31.

Adding to 130214145253 its reverse (352541412031), we get a palindrome (482755557284).

The spelling of 130214145253 in words is "one hundred thirty billion, two hundred fourteen million, one hundred forty-five thousand, two hundred fifty-three".