130220032441238 has 4 divisors (see below), whose sum is σ = 195330048661860. Its totient is φ = 65110016220618.

The previous prime is 130220032441237. The next prime is 130220032441241. The reversal of 130220032441238 is 832144230022031.

It is a semiprime because it is the product of two primes.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 130220032441198 and 130220032441207.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (130220032441237) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32555008110308 + ... + 32555008110311.

It is an arithmetic number, because the mean of its divisors is an integer number (48832512165465).

Almost surely, 2^{130220032441238} is an apocalyptic number.

130220032441238 is a deficient number, since it is larger than the sum of its proper divisors (65110016220622).

130220032441238 is an equidigital number, since it uses as much as digits as its factorization.

130220032441238 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 65110016220621.

The product of its (nonzero) digits is 55296, while the sum is 35.

Adding to 130220032441238 its reverse (832144230022031), we get a palindrome (962364262463269).

The spelling of 130220032441238 in words is "one hundred thirty trillion, two hundred twenty billion, thirty-two million, four hundred forty-one thousand, two hundred thirty-eight".