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13022021113030 = 256266292078107
BaseRepresentation
bin1011110101111110110011…
…1100010101010011000110
31201002220010001002222101101
42331133230330111103012
53201323044401104110
643410122305250314
72512544552103166
oct275375474252306
951086101088341
1013022021113030
114170676486966
12156390863399a
13735c81cc0307
143303aa9005a6
15178aeca8613a
hexbd7ecf154c6

13022021113030 has 16 divisors (see below), whose sum is σ = 23439686688720. Its totient is φ = 5208797626272.

The previous prime is 13022021113001. The next prime is 13022021113061. The reversal of 13022021113030 is 3031112022031.

It is a junction number, because it is equal to n+sod(n) for n = 13022021112989 and 13022021113007.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 5227237 + ... + 7305343.

It is an arithmetic number, because the mean of its divisors is an integer number (1464980418045).

Almost surely, 213022021113030 is an apocalyptic number.

13022021113030 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

13022021113030 is a deficient number, since it is larger than the sum of its proper divisors (10417665575690).

13022021113030 is a wasteful number, since it uses less digits than its factorization.

13022021113030 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2704743.

The product of its (nonzero) digits is 216, while the sum is 19.

Adding to 13022021113030 its reverse (3031112022031), we get a palindrome (16053133135061).

Subtracting from 13022021113030 its reverse (3031112022031), we obtain a palindrome (9990909090999).

The spelling of 13022021113030 in words is "thirteen trillion, twenty-two billion, twenty-one million, one hundred thirteen thousand, thirty".

Divisors: 1 2 5 10 626629 1253258 2078107 3133145 4156214 6266290 10390535 20781070 1302202111303 2604404222606 6511010556515 13022021113030