Base | Representation |
---|---|
bin | 1011110101111110110101… |
… | …1111000000100111000011 |
3 | 1201002220010200012210221012 |
4 | 2331133231133000213003 |
5 | 3201323104213001311 |
6 | 43410123232151135 |
7 | 2512545022263422 |
oct | 275375537004703 |
9 | 51086120183835 |
10 | 13022030203331 |
11 | 4170680625606 |
12 | 156390b6984ab |
13 | 735c83b53aa6 |
14 | 3303abbc92b9 |
15 | 178aed77e78b |
hex | bd7ed7c09c3 |
13022030203331 has 2 divisors, whose sum is σ = 13022030203332. Its totient is φ = 13022030203330.
The previous prime is 13022030203321. The next prime is 13022030203379. The reversal of 13022030203331 is 13330203022031.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13022030203331 - 242 = 8623983692227 is a prime.
It is a super-2 number, since 2×130220302033312 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13022030203297 and 13022030203306.
It is not a weakly prime, because it can be changed into another prime (13022030203321) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6511015101665 + 6511015101666.
It is an arithmetic number, because the mean of its divisors is an integer number (6511015101666).
Almost surely, 213022030203331 is an apocalyptic number.
13022030203331 is a deficient number, since it is larger than the sum of its proper divisors (1).
13022030203331 is an equidigital number, since it uses as much as digits as its factorization.
13022030203331 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1944, while the sum is 23.
Adding to 13022030203331 its reverse (13330203022031), we get a palindrome (26352233225362).
The spelling of 13022030203331 in words is "thirteen trillion, twenty-two billion, thirty million, two hundred three thousand, three hundred thirty-one".
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