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13022122021333 is a prime number
BaseRepresentation
bin1011110101111111001011…
…1101010001000111010101
31201002220101001222122112221
42331133302331101013111
53201323301214140313
643410140312142341
72512550215600405
oct275376275210725
951086331878487
1013022122021333
114170718438857
1215639363979b1
13735c99b91379
143303ba08a805
15178b06869c8d
hexbd7f2f511d5

13022122021333 has 2 divisors, whose sum is σ = 13022122021334. Its totient is φ = 13022122021332.

The previous prime is 13022122021319. The next prime is 13022122021343. The reversal of 13022122021333 is 33312022122031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11184489639684 + 1837632381649 = 3344322^2 + 1355593^2 .

It is a cyclic number.

It is not a de Polignac number, because 13022122021333 - 29 = 13022122020821 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13022122021298 and 13022122021307.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13022122021343) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6511061010666 + 6511061010667.

It is an arithmetic number, because the mean of its divisors is an integer number (6511061010667).

Almost surely, 213022122021333 is an apocalyptic number.

It is an amenable number.

13022122021333 is a deficient number, since it is larger than the sum of its proper divisors (1).

13022122021333 is an equidigital number, since it uses as much as digits as its factorization.

13022122021333 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 13022122021333 its reverse (33312022122031), we get a palindrome (46334144143364).

The spelling of 13022122021333 in words is "thirteen trillion, twenty-two billion, one hundred twenty-two million, twenty-one thousand, three hundred thirty-three".