Base | Representation |
---|---|
bin | 11101100110111110001111… |
… | …100000010010110101000010 |
3 | 122002002001111200221211202220 |
4 | 131212332033200102311002 |
5 | 114032022133342230132 |
6 | 1140542535122551510 |
7 | 36300123454462254 |
oct | 3546761740226502 |
9 | 562061450854686 |
10 | 130221521055042 |
11 | 3854670084962a |
12 | 12731977b08596 |
13 | 5787ab5433951 |
14 | 2422a80589cd4 |
15 | 100c562091a2c |
hex | 766f8f812d42 |
130221521055042 has 64 divisors (see below), whose sum is σ = 285766432441344. Its totient is φ = 39382109061120.
The previous prime is 130221521055019. The next prime is 130221521055091. The reversal of 130221521055042 is 240550125122031.
130221521055042 is digitally balanced in base 4, because in such base it contains all the possibile digits an equal number of times.
It is a junction number, because it is equal to n+sod(n) for n = 130221521054994 and 130221521055012.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 79310473 + ... + 80935740.
It is an arithmetic number, because the mean of its divisors is an integer number (4465100506896).
Almost surely, 2130221521055042 is an apocalyptic number.
130221521055042 is an abundant number, since it is smaller than the sum of its proper divisors (155544911386302).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
130221521055042 is a wasteful number, since it uses less digits than its factorization.
130221521055042 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 160246523.
The product of its (nonzero) digits is 24000, while the sum is 33.
Adding to 130221521055042 its reverse (240550125122031), we get a palindrome (370771646177073).
The spelling of 130221521055042 in words is "one hundred thirty trillion, two hundred twenty-one billion, five hundred twenty-one million, fifty-five thousand, forty-two".
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