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130222131023 is a prime number
BaseRepresentation
bin111100101000111011…
…0000000011101001111
3110110010101220200002202
41321101312000131033
54113143331143043
6135453452112115
712260011564445
oct1712166003517
9413111820082
10130222131023
1150254aa8496
12212a316563b
13c383c0a1ca
146434bacb95
1535c25e01b8
hex1e51d8074f

130222131023 has 2 divisors, whose sum is σ = 130222131024. Its totient is φ = 130222131022.

The previous prime is 130222130989. The next prime is 130222131037. The reversal of 130222131023 is 320131222031.

It is a strong prime.

It is an emirp because it is prime and its reverse (320131222031) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 130222131023 - 26 = 130222130959 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 130222130986 and 130222131004.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (130222131223) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65111065511 + 65111065512.

It is an arithmetic number, because the mean of its divisors is an integer number (65111065512).

Almost surely, 2130222131023 is an apocalyptic number.

130222131023 is a deficient number, since it is larger than the sum of its proper divisors (1).

130222131023 is an equidigital number, since it uses as much as digits as its factorization.

130222131023 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 432, while the sum is 20.

Adding to 130222131023 its reverse (320131222031), we get a palindrome (450353353054).

The spelling of 130222131023 in words is "one hundred thirty billion, two hundred twenty-two million, one hundred thirty-one thousand, twenty-three".