Search a number
-
+
13022221102999 is a prime number
BaseRepresentation
bin1011110101111111100011…
…0111001110111110010111
31201002220121222102112001021
42331133320313032332113
53201324002100243444
643410154211542011
72512552531016263
oct275377067167627
951086558375037
1013022221102999
114170769362329
1215639635ba907
13735cb4572b84
143303c92bd0a3
15178b103dc584
hexbd7f8dcef97

13022221102999 has 2 divisors, whose sum is σ = 13022221103000. Its totient is φ = 13022221102998.

The previous prime is 13022221102993. The next prime is 13022221103051. The reversal of 13022221102999 is 99920112222031.

It is a weak prime.

It is an emirp because it is prime and its reverse (99920112222031) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13022221102999 - 221 = 13022219005847 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13022221102993) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (31) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6511110551499 + 6511110551500.

It is an arithmetic number, because the mean of its divisors is an integer number (6511110551500).

Almost surely, 213022221102999 is an apocalyptic number.

13022221102999 is a deficient number, since it is larger than the sum of its proper divisors (1).

13022221102999 is an equidigital number, since it uses as much as digits as its factorization.

13022221102999 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 69984, while the sum is 43.

The spelling of 13022221102999 in words is "thirteen trillion, twenty-two billion, two hundred twenty-one million, one hundred two thousand, nine hundred ninety-nine".