Base | Representation |
---|---|
bin | 1011110101111111100011… |
… | …0111001111000000011010 |
3 | 1201002220121222102112020010 |
4 | 2331133320313033000122 |
5 | 3201324002100300010 |
6 | 43410154211542350 |
7 | 2512552531016541 |
oct | 275377067170032 |
9 | 51086558375203 |
10 | 13022221103130 |
11 | 4170769362438 |
12 | 15639635ba9b6 |
13 | 735cb4572c55 |
14 | 3303c92bd158 |
15 | 178b103dc620 |
hex | bd7f8dcf01a |
13022221103130 has 32 divisors (see below), whose sum is σ = 31284001310400. Its totient is φ = 3469184442752.
The previous prime is 13022221103081. The next prime is 13022221103131. The reversal of 13022221103130 is 3130112222031.
It is a junction number, because it is equal to n+sod(n) for n = 13022221103097 and 13022221103106.
It is not an unprimeable number, because it can be changed into a prime (13022221103131) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 212959635 + ... + 213020774.
It is an arithmetic number, because the mean of its divisors is an integer number (977625040950).
Almost surely, 213022221103130 is an apocalyptic number.
13022221103130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
13022221103130 is an abundant number, since it is smaller than the sum of its proper divisors (18261780207270).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13022221103130 is a wasteful number, since it uses less digits than its factorization.
13022221103130 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 425981438.
The product of its (nonzero) digits is 432, while the sum is 21.
Adding to 13022221103130 its reverse (3130112222031), we get a palindrome (16152333325161).
The spelling of 13022221103130 in words is "thirteen trillion, twenty-two billion, two hundred twenty-one million, one hundred three thousand, one hundred thirty".
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