Search a number
-
+
13022230031197 is a prime number
BaseRepresentation
bin1011110101111111100101…
…1001010010101101011101
31201002220122121020010020021
42331133321121102231131
53201324011341444242
643410155131152141
72512552666633102
oct275377131225535
951086577203207
1013022230031197
114170773400202
1215639665a5651
13735cb637a92a
143303ca564aa9
15178b110a2b67
hexbd7f9652b5d

13022230031197 has 2 divisors, whose sum is σ = 13022230031198. Its totient is φ = 13022230031196.

The previous prime is 13022230031189. The next prime is 13022230031203. The reversal of 13022230031197 is 79113003222031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12540564882756 + 481665148441 = 3541266^2 + 694021^2 .

It is a cyclic number.

It is not a de Polignac number, because 13022230031197 - 23 = 13022230031189 is a prime.

It is a super-3 number, since 3×130222300311973 (a number of 40 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13022230091197) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6511115015598 + 6511115015599.

It is an arithmetic number, because the mean of its divisors is an integer number (6511115015599).

Almost surely, 213022230031197 is an apocalyptic number.

It is an amenable number.

13022230031197 is a deficient number, since it is larger than the sum of its proper divisors (1).

13022230031197 is an equidigital number, since it uses as much as digits as its factorization.

13022230031197 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 13608, while the sum is 34.

The spelling of 13022230031197 in words is "thirteen trillion, twenty-two billion, two hundred thirty million, thirty-one thousand, one hundred ninety-seven".