Base | Representation |
---|---|
bin | 10010111100110010100… |
… | …010111100101111000101 |
3 | 11121111021011112022011111 |
4 | 102330302202330233011 |
5 | 132313423104110112 |
6 | 2434122200405021 |
7 | 163040205554011 |
oct | 22746242745705 |
9 | 4544234468144 |
10 | 1302223113157 |
11 | 4622a6aa8a9a |
12 | 190467a76771 |
13 | 95a5085c205 |
14 | 47056921541 |
15 | 23d191aa5a7 |
hex | 12f328bcbc5 |
1302223113157 has 2 divisors, whose sum is σ = 1302223113158. Its totient is φ = 1302223113156.
The previous prime is 1302223113119. The next prime is 1302223113181. The reversal of 1302223113157 is 7513113222031.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1042585987041 + 259637126116 = 1021071^2 + 509546^2 .
It is an emirp because it is prime and its reverse (7513113222031) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1302223113157 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1302227113157) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 651111556578 + 651111556579.
It is an arithmetic number, because the mean of its divisors is an integer number (651111556579).
Almost surely, 21302223113157 is an apocalyptic number.
It is an amenable number.
1302223113157 is a deficient number, since it is larger than the sum of its proper divisors (1).
1302223113157 is an equidigital number, since it uses as much as digits as its factorization.
1302223113157 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 7560, while the sum is 31.
Adding to 1302223113157 its reverse (7513113222031), we get a palindrome (8815336335188).
The spelling of 1302223113157 in words is "one trillion, three hundred two billion, two hundred twenty-three million, one hundred thirteen thousand, one hundred fifty-seven".
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