Base | Representation |
---|---|
bin | 11000010000011001… |
… | …00000111110110001 |
3 | 1020121112221111002011 |
4 | 30020030200332301 |
5 | 203132213303213 |
6 | 5552111122521 |
7 | 640464402010 |
oct | 141014407661 |
9 | 36545844064 |
10 | 13022400433 |
11 | 5582895209 |
12 | 2635213441 |
13 | 12c6c158b3 |
14 | 8b771aa77 |
15 | 5133c903d |
hex | 308320fb1 |
13022400433 has 4 divisors (see below), whose sum is σ = 14882743360. Its totient is φ = 11162057508.
The previous prime is 13022400427. The next prime is 13022400449. The reversal of 13022400433 is 33400422031.
It is a happy number.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 33400422031 = 19 ⋅1757916949.
It is not a de Polignac number, because 13022400433 - 217 = 13022269361 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13022400463) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 930171453 + ... + 930171466.
It is an arithmetic number, because the mean of its divisors is an integer number (3720685840).
Almost surely, 213022400433 is an apocalyptic number.
It is an amenable number.
13022400433 is a deficient number, since it is larger than the sum of its proper divisors (1860342927).
13022400433 is an equidigital number, since it uses as much as digits as its factorization.
13022400433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1860342926.
The product of its (nonzero) digits is 1728, while the sum is 22.
Adding to 13022400433 its reverse (33400422031), we get a palindrome (46422822464).
The spelling of 13022400433 in words is "thirteen billion, twenty-two million, four hundred thousand, four hundred thirty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.067 sec. • engine limits •