Base | Representation |
---|---|
bin | 1011110110000010110101… |
… | …1011011010101011000011 |
3 | 1201002222220102212200212112 |
4 | 2331200231123122223003 |
5 | 3201332303332101311 |
6 | 43410421514045535 |
7 | 2512613430032261 |
oct | 275405533325303 |
9 | 51088812780775 |
10 | 13023103003331 |
11 | 4171081152083 |
12 | 1563b6aa198ab |
13 | 7360c51a00a5 |
14 | 330470487431 |
15 | 178b62a4128b |
hex | bd82d6daac3 |
13023103003331 has 2 divisors, whose sum is σ = 13023103003332. Its totient is φ = 13023103003330.
The previous prime is 13023103003291. The next prime is 13023103003363. The reversal of 13023103003331 is 13330030132031.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13023103003331 - 234 = 13005923134147 is a prime.
It is a super-2 number, since 2×130231030033312 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13023103003297 and 13023103003306.
It is not a weakly prime, because it can be changed into another prime (13023103002331) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6511551501665 + 6511551501666.
It is an arithmetic number, because the mean of its divisors is an integer number (6511551501666).
Almost surely, 213023103003331 is an apocalyptic number.
13023103003331 is a deficient number, since it is larger than the sum of its proper divisors (1).
13023103003331 is an equidigital number, since it uses as much as digits as its factorization.
13023103003331 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1458, while the sum is 23.
Adding to 13023103003331 its reverse (13330030132031), we get a palindrome (26353133135362).
The spelling of 13023103003331 in words is "thirteen trillion, twenty-three billion, one hundred three million, three thousand, three hundred thirty-one".
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