Base | Representation |
---|---|
bin | 10010111100110111110… |
… | …010101001000101000111 |
3 | 11121111111022010011022002 |
4 | 102330313302221011013 |
5 | 132314113121104111 |
6 | 2434135022455515 |
7 | 163042324546265 |
oct | 22746762510507 |
9 | 4544438104262 |
10 | 1302311113031 |
11 | 462341743665 |
12 | 19049143459b |
13 | 95a65b60946 |
14 | 470644ab435 |
15 | 23d21c8e63b |
hex | 12f37ca9147 |
1302311113031 has 2 divisors, whose sum is σ = 1302311113032. Its totient is φ = 1302311113030.
The previous prime is 1302311113027. The next prime is 1302311113039. The reversal of 1302311113031 is 1303111132031.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1302311113031 - 22 = 1302311113027 is a prime.
It is a super-2 number, since 2×13023111130312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1302311112994 and 1302311113012.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1302311113039) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 651155556515 + 651155556516.
It is an arithmetic number, because the mean of its divisors is an integer number (651155556516).
Almost surely, 21302311113031 is an apocalyptic number.
1302311113031 is a deficient number, since it is larger than the sum of its proper divisors (1).
1302311113031 is an equidigital number, since it uses as much as digits as its factorization.
1302311113031 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 162, while the sum is 20.
Adding to 1302311113031 its reverse (1303111132031), we get a palindrome (2605422245062).
The spelling of 1302311113031 in words is "one trillion, three hundred two billion, three hundred eleven million, one hundred thirteen thousand, thirty-one".
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