Search a number
-
+
13023113001 = 34341037667
BaseRepresentation
bin11000010000011110…
…01110111100101001
31020121121021200112120
430020033032330221
5203132404104001
65552134301453
7640503430323
oct141017167451
936547250476
1013023113001
115583231608
1226354b7889
1312c7105032
148b7864613
155134ba236
hex3083cef29

13023113001 has 4 divisors (see below), whose sum is σ = 17364150672. Its totient is φ = 8682075332.

The previous prime is 13023112987. The next prime is 13023113039. The reversal of 13023113001 is 10031132031.

13023113001 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13023113001 - 210 = 13023111977 is a prime.

It is not an unprimeable number, because it can be changed into a prime (13023113101) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2170518831 + ... + 2170518836.

It is an arithmetic number, because the mean of its divisors is an integer number (4341037668).

Almost surely, 213023113001 is an apocalyptic number.

It is an amenable number.

13023113001 is a deficient number, since it is larger than the sum of its proper divisors (4341037671).

13023113001 is an equidigital number, since it uses as much as digits as its factorization.

13023113001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4341037670.

The product of its (nonzero) digits is 54, while the sum is 15.

Adding to 13023113001 its reverse (10031132031), we get a palindrome (23054245032).

The spelling of 13023113001 in words is "thirteen billion, twenty-three million, one hundred thirteen thousand, one".

Divisors: 1 3 4341037667 13023113001