Base | Representation |
---|---|
bin | 1011110110000010111000… |
… | …0010011011011100101011 |
3 | 1201002222221011010021101121 |
4 | 2331200232002123130223 |
5 | 3201332313441330443 |
6 | 43410422521200111 |
7 | 2512613612665063 |
oct | 275405602333453 |
9 | 51088834107347 |
10 | 13023113230123 |
11 | 41710869a7677 |
12 | 1563b72330037 |
13 | 7360c7340c49 |
14 | 33047198a3a3 |
15 | 178b638b14ed |
hex | bd82e09b72b |
13023113230123 has 2 divisors, whose sum is σ = 13023113230124. Its totient is φ = 13023113230122.
The previous prime is 13023113230103. The next prime is 13023113230181. The reversal of 13023113230123 is 32103231132031.
It is a weak prime.
It is an emirp because it is prime and its reverse (32103231132031) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13023113230123 - 233 = 13014523295531 is a prime.
It is not a weakly prime, because it can be changed into another prime (13023113230103) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6511556615061 + 6511556615062.
It is an arithmetic number, because the mean of its divisors is an integer number (6511556615062).
Almost surely, 213023113230123 is an apocalyptic number.
13023113230123 is a deficient number, since it is larger than the sum of its proper divisors (1).
13023113230123 is an equidigital number, since it uses as much as digits as its factorization.
13023113230123 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1944, while the sum is 25.
Adding to 13023113230123 its reverse (32103231132031), we get a palindrome (45126344362154).
The spelling of 13023113230123 in words is "thirteen trillion, twenty-three billion, one hundred thirteen million, two hundred thirty thousand, one hundred twenty-three".
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