Base | Representation |
---|---|
bin | 1011110110000010111100… |
… | …0110001110010010001101 |
3 | 1201002222222101120011211011 |
4 | 2331200233012032102031 |
5 | 3201332333014030442 |
6 | 43410424354125221 |
7 | 2512614220024114 |
oct | 275405706162215 |
9 | 51088871504734 |
10 | 13023131001997 |
11 | 4171095a35976 |
12 | 1563b78280811 |
13 | 7360cac2414c |
14 | 330474094c7b |
15 | 178b65222117 |
hex | bd82f18e48d |
13023131001997 has 2 divisors, whose sum is σ = 13023131001998. Its totient is φ = 13023131001996.
The previous prime is 13023131001977. The next prime is 13023131002039. The reversal of 13023131001997 is 79910013132031.
13023131001997 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 8037797680201 + 4985333321796 = 2835101^2 + 2232786^2 .
It is a cyclic number.
It is not a de Polignac number, because 13023131001997 - 243 = 4227037979789 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13023131001977) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6511565500998 + 6511565500999.
It is an arithmetic number, because the mean of its divisors is an integer number (6511565500999).
Almost surely, 213023131001997 is an apocalyptic number.
It is an amenable number.
13023131001997 is a deficient number, since it is larger than the sum of its proper divisors (1).
13023131001997 is an equidigital number, since it uses as much as digits as its factorization.
13023131001997 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 30618, while the sum is 40.
The spelling of 13023131001997 in words is "thirteen trillion, twenty-three billion, one hundred thirty-one million, one thousand, nine hundred ninety-seven".
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