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13023131001997 is a prime number
BaseRepresentation
bin1011110110000010111100…
…0110001110010010001101
31201002222222101120011211011
42331200233012032102031
53201332333014030442
643410424354125221
72512614220024114
oct275405706162215
951088871504734
1013023131001997
114171095a35976
121563b78280811
137360cac2414c
14330474094c7b
15178b65222117
hexbd82f18e48d

13023131001997 has 2 divisors, whose sum is σ = 13023131001998. Its totient is φ = 13023131001996.

The previous prime is 13023131001977. The next prime is 13023131002039. The reversal of 13023131001997 is 79910013132031.

13023131001997 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 8037797680201 + 4985333321796 = 2835101^2 + 2232786^2 .

It is a cyclic number.

It is not a de Polignac number, because 13023131001997 - 243 = 4227037979789 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13023131001977) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6511565500998 + 6511565500999.

It is an arithmetic number, because the mean of its divisors is an integer number (6511565500999).

Almost surely, 213023131001997 is an apocalyptic number.

It is an amenable number.

13023131001997 is a deficient number, since it is larger than the sum of its proper divisors (1).

13023131001997 is an equidigital number, since it uses as much as digits as its factorization.

13023131001997 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 30618, while the sum is 40.

The spelling of 13023131001997 in words is "thirteen trillion, twenty-three billion, one hundred thirty-one million, one thousand, nine hundred ninety-seven".