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1302313311113 is a prime number
BaseRepresentation
bin10010111100110111111…
…011000001101110001001
311121111111110020211111112
4102330313323001232021
5132314114201423423
62434135141540105
7163042352332553
oct22746773015611
94544443224445
101302313311113
11462342a05061
12190492114635
1395a66450299
14470648c04d3
1523d22075a78
hex12f37ec1b89

1302313311113 has 2 divisors, whose sum is σ = 1302313311114. Its totient is φ = 1302313311112.

The previous prime is 1302313311107. The next prime is 1302313311127. The reversal of 1302313311113 is 3111133132031.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1291830008569 + 10483302544 = 1136587^2 + 102388^2 .

It is an emirp because it is prime and its reverse (3111133132031) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1302313311113 - 214 = 1302313294729 is a prime.

It is not a weakly prime, because it can be changed into another prime (1302313316113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 651156655556 + 651156655557.

It is an arithmetic number, because the mean of its divisors is an integer number (651156655557).

Almost surely, 21302313311113 is an apocalyptic number.

It is an amenable number.

1302313311113 is a deficient number, since it is larger than the sum of its proper divisors (1).

1302313311113 is an equidigital number, since it uses as much as digits as its factorization.

1302313311113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 486, while the sum is 23.

Adding to 1302313311113 its reverse (3111133132031), we get a palindrome (4413446443144).

The spelling of 1302313311113 in words is "one trillion, three hundred two billion, three hundred thirteen million, three hundred eleven thousand, one hundred thirteen".