Base | Representation |
---|---|
bin | 10010111100111000011… |
… | …001001010101001101011 |
3 | 11121111112000010020111101 |
4 | 102330320121022221223 |
5 | 132314123212241021 |
6 | 2434140023142231 |
7 | 163042506440341 |
oct | 22747031125153 |
9 | 4544460106441 |
10 | 1302321212011 |
11 | 462347411126 |
12 | 1904948a4977 |
13 | 95a67c88581 |
14 | 47065979991 |
15 | 23d22ad6a91 |
hex | 12f3864aa6b |
1302321212011 has 2 divisors, whose sum is σ = 1302321212012. Its totient is φ = 1302321212010.
The previous prime is 1302321212009. The next prime is 1302321212033. The reversal of 1302321212011 is 1102121232031.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1302321212011 - 21 = 1302321212009 is a prime.
Together with 1302321212009, it forms a pair of twin primes.
It is a self number, because there is not a number n which added to its sum of digits gives 1302321212011.
It is not a weakly prime, because it can be changed into another prime (1302321212081) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 651160606005 + 651160606006.
It is an arithmetic number, because the mean of its divisors is an integer number (651160606006).
Almost surely, 21302321212011 is an apocalyptic number.
1302321212011 is a deficient number, since it is larger than the sum of its proper divisors (1).
1302321212011 is an equidigital number, since it uses as much as digits as its factorization.
1302321212011 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 144, while the sum is 19.
Adding to 1302321212011 its reverse (1102121232031), we get a palindrome (2404442444042).
The spelling of 1302321212011 in words is "one trillion, three hundred two billion, three hundred twenty-one million, two hundred twelve thousand, eleven".
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