Base | Representation |
---|---|
bin | 10010111100111000011… |
… | …101010101000010100101 |
3 | 11121111112002011200020121 |
4 | 102330320131111002211 |
5 | 132314124002200031 |
6 | 2434140102401541 |
7 | 163042521633436 |
oct | 22747035250245 |
9 | 4544462150217 |
10 | 1302322303141 |
11 | 462347a96992 |
12 | 1904951302b1 |
13 | 95a6827b102 |
14 | 47065b8148d |
15 | 23d22c50011 |
hex | 12f387550a5 |
1302322303141 has 2 divisors, whose sum is σ = 1302322303142. Its totient is φ = 1302322303140.
The previous prime is 1302322303097. The next prime is 1302322303189. The reversal of 1302322303141 is 1413032232031.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 813622040100 + 488700263041 = 902010^2 + 699071^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1302322303141 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1302322300141) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 651161151570 + 651161151571.
It is an arithmetic number, because the mean of its divisors is an integer number (651161151571).
Almost surely, 21302322303141 is an apocalyptic number.
It is an amenable number.
1302322303141 is a deficient number, since it is larger than the sum of its proper divisors (1).
1302322303141 is an equidigital number, since it uses as much as digits as its factorization.
1302322303141 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2592, while the sum is 25.
Adding to 1302322303141 its reverse (1413032232031), we get a palindrome (2715354535172).
The spelling of 1302322303141 in words is "one trillion, three hundred two billion, three hundred twenty-two million, three hundred three thousand, one hundred forty-one".
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