Base | Representation |
---|---|
bin | 11101100111001000111011… |
… | …110001010110100000100111 |
3 | 122002010011010202202200221021 |
4 | 131213020323301112200213 |
5 | 114032214141243023221 |
6 | 1140552114221032011 |
7 | 36301011113555404 |
oct | 3547107361264047 |
9 | 562104122680837 |
10 | 130233001142311 |
11 | 38550561a83061 |
12 | 127340406b5607 |
13 | 5788bc49608b2 |
14 | 242344d10b2ab |
15 | 100c9d4d64041 |
hex | 76723bc56827 |
130233001142311 has 2 divisors, whose sum is σ = 130233001142312. Its totient is φ = 130233001142310.
The previous prime is 130233001142263. The next prime is 130233001142347. The reversal of 130233001142311 is 113241100332031.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 130233001142311 - 219 = 130233000618023 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (130233001142711) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65116500571155 + 65116500571156.
It is an arithmetic number, because the mean of its divisors is an integer number (65116500571156).
Almost surely, 2130233001142311 is an apocalyptic number.
130233001142311 is a deficient number, since it is larger than the sum of its proper divisors (1).
130233001142311 is an equidigital number, since it uses as much as digits as its factorization.
130233001142311 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1296, while the sum is 25.
Adding to 130233001142311 its reverse (113241100332031), we get a palindrome (243474101474342).
The spelling of 130233001142311 in words is "one hundred thirty trillion, two hundred thirty-three billion, one million, one hundred forty-two thousand, three hundred eleven".
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